Wave Velocity Calculation: y = 0.02 sin[ pi(30x - 400t)] in SI units

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The wave described by the equation y = 0.02 sin[ pi(30x - 400t)] has a velocity of 40/3 m/s. The initial approach mistakenly calculated the derivative for maximum velocity instead of the wave's propagation velocity. The correct method involves identifying the wave number (k) and angular frequency (ω) from the equation. By using the relationship v = ω/k, the calculation confirms that the wave velocity is indeed 40/3 m/s. Understanding the distinction between point velocity and wave velocity is crucial in solving such problems.
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Homework Statement


For a wave described by y = 0.02 sin[ pi(30x - 400t)] (SI units), the velocity of the wave (in m/s) is

a) 3/40 b) 40/3 c) (60pi)/400 d)400/(60pi) e) 400

Homework Equations

The Attempt at a Solution


I found the derivative of the function as v= -25.132 cos[pi(30x-400t)] so I assumed the velocity is 25.132 m/s which is none of the options and the correct answer is 40/3.
 
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they wanted the velocity of the disturbance along the string, not the maximum velocity for one point on the string.
the velocity is hiding in the trig function's argument (kx-ωt) ≈ k(x-vt)
 
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That makes sense! So right now the kx-ωt is (30pi)x-(400pi)t, where k= 30pi. So factoring out 30pi we get v=(400pi)/(30pi) which is 40/3. Thank you!
 
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