Wavelength of visible light under a oil leak

AI Thread Summary
The discussion focuses on calculating the strongest transmitted intensity of visible light under a kerosene slick in the Persian Gulf, using thin-film interference principles. The thickness of the slick is given as 460 nm, and the refractive index of kerosene is 1.2. The equation for minima in dark film is applied, leading to the expression 2L = (m + 1/2)λ / 1.2. The wavelength of light is then solved within the visible spectrum range of 0.4 to 0.75 µm, resulting in an answer of 442 nm. Participants are encouraged to verify the steps taken in the solution for accuracy.
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A disabled tanker leaks kerosene (n=1.2) into the Persian Gulf, creating a large slick on the top of water (n=1.3). If you are scuba diving directly under the region of the slick, whose thickness is 460nm, while the Sun is overhead, for which wavelength(s) of visible light is the transmitted intensity strongest?
 
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This is what i can do:
1) consider this problem as thin-film interference.
2) the strongest intensity occurs at minima dark film in air ( because the observer is diving) ? I cannot explain why!
3) we set up the equation for minima dark film in air: 2L=(m+1/2)\lamda)/1.2
? and put it in the interval from 0.4 to 0.75
4) Solve for lamda.

Any comment?
 
I got the answer 442nm. But somehow, I'm not sure about my steps in the solution. Anyhelp?
 
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