What are the Moments of Inertia for a Ball and Hoop on a Ramp?

AI Thread Summary
The discussion focuses on calculating the moments of inertia, angular speeds, and other related parameters for a hollow ball and hoop rolling down a ramp. The ball reaches the bottom in 5 seconds, while the hoop takes 7 seconds, prompting the need for specific equations to solve for velocity, angular speed, moment of inertia, rotational kinetic energy, and angular momentum. The user correctly applied the distance formula for part A but struggled with the remaining parts, particularly in determining angular velocity and moments of inertia. Clarifications were provided regarding the relationships between linear and angular quantities, as well as the correct formulas for moments of inertia for both objects. The user expressed uncertainty about their calculations for the moments of inertia and whether they were marked incorrectly due to missing units.
vector7
Messages
2
Reaction score
0

Homework Statement


A hollow, 50N ball and a 50N hoop are released from rest at the top of a 3m long ramp. Both objects have a diameter of .5m. If the ball reaches the bottom in 5s, and the hoop in 7s, find (for each object):
a. velocity at the bottom
b. angular speed at bottom
c. moment of intertia at bottom
d. rotational kinetic energy at bottom
e. angular momentum at bottom


Homework Equations



d=1/2at^2+Vot
I=mr^2

That's another part of the problem: I don't know the needed equations

The Attempt at a Solution



I answered part A correctly, using d=1/2at^2, but the rest I bombed. I attempted using 2πr/t for part B, I=mr^2 for C, KE=1/2mv^2 for D, and mvr for E, all of which were wrong.
Any help would be appreciated.
 
Physics news on Phys.org
vector7 said:

Homework Statement


A hollow, 50N ball and a 50N hoop are released from rest at the top of a 3m long ramp. Both objects have a diameter of .5m. If the ball reaches the bottom in 5s, and the hoop in 7s, find (for each object):
a. velocity at the bottom
b. angular speed at bottom
c. moment of intertia at bottom
d. rotational kinetic energy at bottom
e. angular momentum at bottom


Homework Equations



d=1/2at^2+Vot
I=mr^2

That's another part of the problem: I don't know the needed equations

The Attempt at a Solution



I answered part A correctly, using d=1/2at^2, but the rest I bombed. I attempted using 2πr/t for part B, I=mr^2 for C, KE=1/2mv^2 for D, and mvr for E, all of which were wrong.
Any help would be appreciated.

From the sound of things, I assume there should have been a stipulation that there is no slipping occurring (that is, all motion is a result of rolling only, not sliding and rolling). Otherwise, portions of the problem would be indeterminate without additional information.

That said, for part B, your formula 2πr/t was not quite correct, but your thoughts are probably on the right track. The units of that formula would be m/s, which is linear velocity, but what you are looking for is angular velocity, which would be in units of radians/s. Think about the relationship between the linear velocity at the bottom and how fast the objects must be rotating to maintain that speed.

For Part C, are you expected to actually calculate the moments of inertia? If so, things will be a bit more complicated. If not, your formula should be correct for the hoop (assuming a thin-walled hoop, if it has a given thickness you will need to take the average radius). You should be able to look up the moment of inertia for a hollow sphere.

Parts D and E will require the moments of inertia for each object from Part C. You should have formulas for both Energy and Momentum. Remember, they are similar in nature to linear Energy/Momentum equations ( E = (1/2) m v2 and p = m v).

I hope that gets you on the right track. If I've confused you, please let me know.
 
Alright I mostly understand everything now, thanks. But I still have a problem on part C, with the moment of inertia at the bottom. For the ball, i used I=2/3mr^2, which yielded 2.08, and for the hoop I used I=mr^2 and got 3.13, but I was still marked wrong. I'm not sure wether the work is wrong or wether it was marked just because I left out the units.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top