What Determines the Number of Real Roots in a Quadratic Equation?

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The discussion focuses on determining the conditions for the quadratic equation px^2 + qx + r = 0 to have different types of real roots based on the discriminant. The discriminant, represented as q^2 - 4pr, indicates that for two different real roots, it must be greater than zero; for two equal real roots, it must equal zero; and for no real roots, it must be less than zero. Participants confirm that using the discriminant is the correct approach, even when coefficients are variables. Additionally, they explore specific cases involving the variable k in different quadratic equations, applying the same discriminant principles to find conditions for real roots. Understanding these conditions is crucial for solving quadratic equations effectively.
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Homework Statement


State the condition for the equation px^2 + qx + r = 0 to have:
a)two different real roots
b)two equal real roots
c)no real roots

Homework Equations


b^2-4ac maybe?

The Attempt at a Solution


I missed a class due to ailments and now have to catch up on missed work. I can't find what the question means by state the condition. All I need to know is what that even means, and maybe where to start working.

I've tried using the discriminant of the equation but I don't know what to do because the coefficients are variables, even the constant is a variable. Any help would be great, am I even on the right track with using discriminants?

I just tried using the discriminant of the equation with variables and for each a,b,c I came out with q^2-4pr > 0, q^2-4pr=0, q^2-4pr<0 respectively. I'm not sure if that is correct though.
 
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NO PROBLEM hyzon!
BY THE WAY WHAT YOU ARE THINKING IS CORRECT!YES THAT DISCRIMINANT WILL CERTAINLY HELP YOU & YOU ARE IN THE RIGHT WAY!
FOR ANY QUADRATIC EQUATION px2+qx+r=0
we have solution of x=(-q(+or-)squareroot(q2-4pr))/(2*p)
WELL IT IS MORE POPULAR AS b^2-4a*c.
a)for roots to be real we just want the term inside the root to be greater than or equal to zero.
=>b^2-4a*c>=0
OR HERE IN THIS CASE:
q^2-4pr>=0
=>q2>=4pr is the required condition for real roots.
IF THIS IS NOT SO THEN THE ROOT'S ARE NOT REAL AND ARE THUS IMAGINARY.
THUS a) AND c) ARE DONE.
b)HERE b^2-4ac=0 is condition for real roots.
=>q^2-4pr=0
=>q2=4pr is the required condition for equal roots.
 
Thanks, yeah so I get that now. But I'm stumped again on the same topic.

For what values of k does each equation have two different real roots?
a) x2+kx+1=0

I used the discriminant

k^2-4(1)(1)
k^2-4
k-2
k>2, k<(-2) or |k|>2

I understand that one, but question b) has k in the a position not b.

b)kx^2+4x-3=0

I put it in discriminant form

4^2-4(k)(-3)

Now what? How do I find the values of k to have two different real roots?
 
You use the condition discriminant > 0 like before, only it's a bit simpler to get k!
 
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