I What is the approximate impedance of an RF plasma "antenna"?

Click For Summary
The discussion centers on the challenges of determining the appropriate impedance for an RF plasma antenna, particularly for a plasma cleaning chamber. Users have noted that the required RF power to create plasma decreases as the vacuum level increases, but the impedance values suggested range widely from 3 kOhm to milliohm. There is mention of the need for a matching network to optimize the RF amplifier design, with a focus on using a 13.56 MHz source. The conversation also highlights the differences between DC and RF excitation methods for plasma, with RF being more effective when combined with a heating element to initiate the discharge. Overall, participants are seeking specific impedance data to aid in their experimental designs for plasma generation.
Voltux
Messages
29
Reaction score
3
I've searched high and low for data regarding this from scientific papers to books and I cannot find anything in regards to the approximate impedance to excite a vacuum vessel to plasma state.

In particular I want to built a RF Plasma cleaning chamber, however, I am not sure how to design the matching network for the field. I have tried using low power ~2W approximately 20-50ohms impedance, however, I was unable to create a plasma.

I have been reading that the required RF power to excite a gas to plasma state decreases quite a large amount as it approaches a vacuum and then shoots up exponentially as the vacuum level approaches a perfect vacuum.

Anyway, what sort of impedance should I design my RF amplifier with in order to excite some plasma? Does anyone happen to have data on this? Typically I would determine this experimentally, but I lack a tunable matching network and since I plan on designing this amplifier from the ground up it would be easier to get an idea of what impedance to expect!
 
Physics news on Phys.org
If we pump down a glass tube of air and try to pass a discharge through it, I know from experiment that it requires about 5 kV DC. I suggest using a parallel tuned circuit to step up your power to several kV. It seems probable that the plasma is a non linear load anyway, so the impedance will change with power.
 
tech99 said:
If we pump down a glass tube of air and try to pass a discharge through it, I know from experiment that it requires about 5 kV DC. I suggest using a parallel tuned circuit to step up your power to several kV. It seems probable that the plasma is a non linear load anyway, so the impedance will change with power.
I also understand from a colleague that to excite a 12 inch fluorescent tube with RF he requires about 10W of RF or more.
 
From my understanding the excitation of plasma has different mechanisms for DC breakdown vs RF. I believe the RF is a means of magnetic excitation whereas the DC breaks off an electron or something like that. I can't remember off the top of my head.

I have done the DC method and I believe I used about 3kV under vacuum in a glass bottle. I'm sure this differs depending on distance. I've also heard that you can more easily ignite plasma via RF if you have a heating element to send out electrons to "strike" the plasma.

The problem with the DC method was that my connectors got so hot to the point it was melting my vacuum tubing, and cracked my glass vessel. I'd like to try the RF method using a 13.56MHz RF source. The problem is that I've heard everything from 3kOhm to mOhm impedance and I'm not sure how to go about that. I just recently tried to ignite a plasma ball with a few watts but I had nothing.

So I'm looking at designing a small 15W RF Amplifier to play around with for testing, and then building a 100W system once I understand the matching bit more so I don't waste a $30 FET. I'd love to start some research into thin films, deposition, and play around with plasma cleaning!
 
Voltux said:
From my understanding the excitation of plasma has different mechanisms for DC breakdown vs RF. I believe the RF is a means of magnetic excitation whereas the DC breaks off an electron or something like that. I can't remember off the top of my head.

I have done the DC method and I believe I used about 3kV under vacuum in a glass bottle. I'm sure this differs depending on distance. I've also heard that you can more easily ignite plasma via RF if you have a heating element to send out electrons to "strike" the plasma.

The problem with the DC method was that my connectors got so hot to the point it was melting my vacuum tubing, and cracked my glass vessel. I'd like to try the RF method using a 13.56MHz RF source. The problem is that I've heard everything from 3kOhm to mOhm impedance and I'm not sure how to go about that. I just recently tried to ignite a plasma ball with a few watts but I had nothing.

So I'm looking at designing a small 15W RF Amplifier to play around with for testing, and then building a 100W system once I understand the matching bit more so I don't waste a $30 FET. I'd love to start some research into thin films, deposition, and play around with plasma cleaning!
You could experiment with DC and RF operation of the little NE2 neon bulb, which requires about 100 volts.
 
Thread 'Some confusion with the Binding Energy graph of atoms'
My question is about the following graph: I keep on reading that fusing atoms up until Fe-56 doesn’t cost energy and only releases binding energy. However, I understood that fusing atoms also require energy to overcome the positive charges of the protons. Where does that energy go after fusion? Does it go into the mass of the newly fused atom, escape as heat or is the released binding energy shown in the graph actually the net energy after subtracting the required fusion energy? I...
Hello everyone, I am trying to calculate the energy loss and straggling of alpha particles with same energy, I used LISE++ to obtain the energy loss in every layer of the materials using Spectrometer Design of LISE++, but I can only calculate the energy-loss straggling layer by layer. Does anyone know the way to obtain the energy-loss straggling caused by every layer? Any help would be appreciated. J.