What is the Correct Calculation for the Inertia Tensor in a 2D Rotation?

AI Thread Summary
The discussion centers on calculating the inertia tensor for a 2D rotation in the x-y plane, with specific focus on the components I_{xx}, I_{yy}, and I_{xy}. The original poster questions their professor's calculation of I_{xx} and clarifies that it should be based on the distance from the y-axis, not the x-axis. The importance of both diagonal and off-diagonal terms in the inertia tensor is emphasized, especially for rotations about any axis in the plane. Additionally, the relationship between the inertia tensor and angular momentum is highlighted, noting that off-diagonal terms do not contribute when angular velocity aligns with principal axes. Understanding the products of inertia is seen as crucial for grasping the full implications of rotational dynamics.
CrusaderSean
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my homework problem deals w/ rotation in x-y plane. so the tensor is only 2d. inertial tensor still seems obscure to me... my question for now is purely mathematical. assuming the basis are (x,y). I calculated the components of I, is the following correct?
I_{xx} = m_i y_{i}^{2}
I_{yy} = m_i x_{i}^{2}
I_{xy} = I_{yx} = - m_i x_i y_i

for some reason my professor wrote...
I_{xx} = m_i x_{i}^{2}
and I'm pretty sure its not right
 
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You're fine (besides the missing summation symbols). Think of it this way: if you are rotating about the x-axis, would your inertia depend on where you are along the x-axis or how far away you are from the x-axis.
 
what about the off diagonal terms? are they moments about x=y line?... also do you need orthogonal basis for calculating inertial tensor? from the general definition it doesn't look like a requirement.
 
Sorry, I don't have a good analogy in mind for the products of inertia; maybe someone else reading the thread can help us out. I guess it comes into play when you have rotation that is not along one of the principal axes.
I suppose you could calculate the inertial tensor using a different basis, but wouldn't that just complicate the algebra(and unnecessarily at that)? I'm sorry if I haven't been much help.
 
The full tensor (diagonal and off diagonal terms) is important for rotations about any axis through the origin in the x.y plane, not just the y = x line. The tensor product of I with the angular velocity vector gives the angular momentum vector. When the angular velocity vector is along the x or y axes, the off diagonal terms do not contribute.
 
I can see why angular momentum is in same direction as angular velocity if object rotates about principal axes only. My textbook derives the inertia tensor through rotational kinetic energy calculation. I can see that it relates energy w/ velocity... but i don't understand in what way products of inertia describe the relationship... perhaps i just need to do some problems and see how it all works out.
 
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