What is the Force on Charge B Due to Charges A and C?

AI Thread Summary
To determine the force on charge B due to charges A and C, the relevant formula is FE=kq1q2/r². The calculated force from charge A on B (FAB) is 0.19 N, while the force from charge C on B (FCB) is -1.29 N. The next step involves finding the resultant force vector, which requires knowing the direction of each force. The absence of a diagram and the charge value for B complicates the analysis. Understanding the vector direction is essential for accurately calculating the net force on charge B.
euphoriax
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Homework Statement



Three charges A, B and C with charges respectively +3.2 x 10-6 C and -7.8 x 10-6 C are placed as seen in the diagram. What is the force on B because of A and C?

Homework Equations



FE=kq1q2/r2

The Attempt at a Solution



dAB = 2.5m
dCB= 1.5m
k= 9.0x109 Nm2/c2

FAB= kq1q2/r2
= (9.0x109)(3.2x10-6)(41.4x10-6)/(2.5)2
= 0.19 N

FCB= kq1q2/r2
= (9.0x109)(-7.8x10-6)(41.4x10-6)
= -1.29 N

from here on, I'm not really sure what I am supposed to do...
any help would be aprreciated

thanks!
 
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You didn't show the diagram, nor list the charge on B (I assume it's 41.6 uC) but you need to find the direction of the resultant vector.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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