What is the force on the resting ball from the two wooden boards?

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The discussion centers on calculating the force exerted on a 100 N ball by two wooden boards at a 45-degree angle. One participant calculated the force from each board to be 70.71 N using the formula 100cos(45). To verify this, a free body diagram is suggested to analyze the forces acting on the ball. The equilibrium condition must be satisfied, meaning the sum of the forces should equal zero. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


View the file below. Disregarding friction, how much force does each board of wood put on the 100 N ball?
http://desmond.imageshack.us/Himg841/scaled.php?server=841&filename=physics.jpg&res=landing
 
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Have a go yourself first.
 
I got 70.71 N by doing 100cos(45). I have no idea whether or not this is correct.
 
joel amos said:
I got 70.71 N by doing 100cos(45). I have no idea whether or not this is correct.

There are two boards exerting contact forces on the ball. Call these each F. Draw a free body diagram, and write down the equations in order for the ball to be in equilibrium.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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