What is the magnitude of the magnetic field?

AI Thread Summary
To determine the magnitude of the magnetic field for a Tl atom with a magnetic moment of 1.611 µn and an NMR frequency of 3.90 MHz, the relationship between torque, magnetic moment, and magnetic field is essential. The user struggles with incorporating the unknown radius into their calculations, indicating a need for a clearer approach to the problem. Suggestions include researching concepts like Larmor precession to better understand the relationship between frequency and magnetic field strength. The discussion emphasizes the importance of correctly applying relevant equations to solve for the magnetic field. Ultimately, a comprehensive understanding of the physics involved is crucial for finding the solution.
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Homework Statement



The nucleus of a Tl atom (Atomic mass = 203, element #81) has a magnetic moment of 1.611 µn. A magnetic field is applied to it and its NMR frequency determined to be 3.90 MHz. What is the magnitude of the magnetic field?

Homework Equations



torque = magnetic moment x magnetic field
radius = mv/qB
v = rw
Fcentripetal = mv^2/r

The Attempt at a Solution


I tried (magnetic moment x magnetic field)/radius = mv^2/r but this always leaves me with r in the equation, which is unknown.
 
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You can try looking in your textbook, or do an online search, for "Larmor precession" or "precession of magnetic moment" or something along those lines.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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