What is the net force and power in a lawnmower system?

AI Thread Summary
The discussion revolves around calculating the net force and power in a lawnmower system, where a person pulls a 20 kg lawnmower with a force of 25 N at an angle of 15 degrees. The participants clarify that the net force should only consider horizontal forces, excluding any vertical components of gravity since the lawnmower is not on an incline. They confirm the calculations for work done, heat generated by friction, and the rate of work done, ultimately leading to the correct final speed of the lawnmower. The problem is resolved by focusing on the horizontal motion and forces acting in that direction. The participants successfully arrive at the solution after addressing misconceptions about the forces involved.
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[SOLVED] The NET FORCE and a lawnmower

Homework Statement


Well I am working on a question here and am finding trouble with one part. The answers are in brackets. The trouble I am having is with part c, where i believe you have to find the accleration then the time to work out power which is equal to work over time.

A person pulls on a 20 kg lawn mower with 25 N and moves it 4.5 m. The handle of the lawnmower in inclined at 15 degrees above the horizontal and the friction co-effiecient is 0.1 If vi=0 find
a.)amount of work done by person (108.7)
b.)amount of heat energy generated by friction (85.3)
c.)rate at which the person does work (18.6 Watts)
d.)the final speed of the lawnmower(1.53)



Homework Equations



p = w/t, F=ma ---> a =F/m

The Attempt at a Solution


Well part a is basicaly w= fcos15 * 4.5 m
and b is finding out friction by using force diagrams and finding Fn
but c i am not sure how to find the accel and consequently the time.

wat is the net force in the system? please help. thank you.
 
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The net force on the system in the direction of motion is the sum of EVERY force acting on the object in that direction or the negative of that direction. In this case, your forces to be summed will be any forces acting in the horizontal direction. Can you tell me which forces fit this description?
 
well the forces wrking in that direction are friction, the person pulling and the gravity so i would think that the net force would be Fpull - mgsin15 - Ff

but the answer i get just doesn't workout

thanks
 
OK, by my understanding, the problem does not say that the person is pulling the lawnmower up or down a hill. How can there be a component of gravity involved if the object is not moving along a slope?
 
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i think we have to assume its going up
 
I agree with G01. The lawn mower is not moving up an incline, the handle is at an angle of 15 degrees, and the force of the person pulling it is directed along that handle.
 
physicsperson said:
i think we have to assume its going up

As hage pointed out. We do not have to assume this. Think of the man pulling at the angle of the handle, but the lawn mower still moving horizontally.
 
Ya, you guys were right! Thank you so much! Solved!
 
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