What is the solution to this transformer problem?

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Homework Help Overview

The discussion revolves around a transformer problem involving equivalent circuits, turns ratios, and power calculations. Participants are examining the relationships between load resistance, source resistance, and the transformer characteristics, specifically focusing on how to approach the problem and interpret the given equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to create an equivalent circuit for the transformer and whether the turns ratio is being interpreted correctly. There are discussions about the values used for resistances and the implications of those values on power calculations.

Discussion Status

Some participants have offered insights into the turns ratio and its effect on the circuit, while others are exploring discrepancies in power calculations and questioning the assumptions made about resistance values. There is an ongoing examination of different parts of the problem without a clear consensus on the correct approach.

Contextual Notes

Participants are working with specific values for resistances and turns ratios, and there is mention of potential confusion regarding the correct interpretation of these values in the context of the problem. The discussion includes references to parts (a) and (b) of the problem, indicating a structured approach to the homework assignment.

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Homework Statement



[PLAIN]http://img192.imageshack.us/img192/8428/circuits.png

Homework Equations



\frac{V_L}{V_s} = \frac{nR_L}{n^2 R_s + R_L}

R_s = \frac{R_L}{n^2}

P = \frac{V_L^2}{R_L}

The Attempt at a Solution



How should I go about solving this problem? Do I have to convert it to an equivalent circuit? If so how would the end result look exactly? I haven't seen any good examples in the book of creating equivalent circuits of transformers so I'm a little unsure of what to do.
 
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It looks like n2 is their way of expressing the turns ration of that transformer, 1:n2. So in place of the transformer with 8k in its secondary, you can show a new resistor RS in series with your resistor R, that new resistor bring RL transformed by the square of the turns ratio, as they indicate.
 
NascentOxygen said:
It looks like n2 is their way of expressing the turns ration of that transformer, 1:n2. So in place of the transformer with 8k in its secondary, you can show a new resistor RS in series with your resistor R, that new resistor bring RL transformed by the square of the turns ratio, as they indicate.

In part a) I found n2 to be 10, but how do I find the max power now? I used the equation I posted in the OP to find the load voltage then used P=\frac{V_L^2}{R_L} but I get 115.2 W as power when the book has 10,000 W roughly. Perhaps it's because I use the wrong value for R_s. I used 20 Ohms. Should it be different? Or it could be because of the n value I use. I put in 10.
 
Last edited:
VitaX said:
In part a) I found n2 to be 10
as do I
but how do I find the max power now?
Are you talking about part (a) or part (b)?
I used the equation I posted in the OP to find the load voltage then used P=\frac{V_L^2}{R_L} but I get 115.2 W as power when the book has 10,000 W roughly.
It can't be thousands of watts. Isn't that a 20 ohm source resistance? So you want the transformed impedances to be of that order, too, so the current from the 120v source is going to be less than 3 amps. (Even were you to short circuit the transformer windings, that 20 ohm will limit the current to 6 amps.)
Perhaps it's because I use the wrong value for R_s. I used 20 Ohms. Should it be different?
I see nothing to indicate a different Rs.
Or it could be because of the n value I use. I put in 10.
In part (b) you are told n1 is 5, and required to find the new n2. So there is no place for using an n of 10.

FWIW, I calculate 1.3125 A is drawn from the 120v supply, in part (b).
 
Last edited:
NascentOxygen said:
as do I

Are you talking about part (a) or part (b)?

It can't be thousands of watts. Isn't that a 20 ohm source resistance? So you want the transformed impedances to be of that order, too, so the current from the 120v source is going to be less than 3 amps. (Even were you to short circuit the transformer windings, that 20 ohm will limit the current to 6 amps.)

I see nothing to indicate a different Rs.

In part (b) you are told n1 is 5, and required to find the new n2. So there is no place for using an n of 10.

FWIW, I calculate 1.3125 A is drawn from the 120v supply, in part (b).

Yeah I was talking about part a) Apparently some others were able to get the 10,000 W power for part a that was int he back of the book though I couldn't really follow what they did.
 

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