What is the source of curvature in an accelerating frame?

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PeterDonis said:
I'll respond to this with another question: how can ##\nabla^2 \Phi## be nonzero when ##\rho## is zero, which it is everywhere outside the source? Doesn't that violate Poisson's equation?

(Hint: you might want to check the actual definition of the Laplacian operator ##\nabla^2## in spherical coordinates.)
This is cool, yes it should violate it unless ##\nabla^2\Phi## is zero which it is according to the definition of Lapalacisn operator. Thank you.