What is the velocity of a proton with an energy of 0.12 keV?

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To calculate the velocity of a proton with an energy of 0.12 keV, the energy must first be converted from electronvolts to joules, which involves multiplying by the charge of an electron. The formula E = 0.5mv^2 is used to relate energy to velocity, leading to the equation v = sqrt(2E/m). A common mistake is dividing instead of multiplying during the conversion process. The correct calculation results in a velocity of approximately 1.5 x 10^5 m/s for the proton.
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Homework Statement



Calculate the veolcity of a proton of energy 0.12 keV

proton mass = 1.7 x 10^-27

Homework Equations


The Attempt at a Solution



I thought...

0.12 keV = 120 eV

120/1.60 x 10^-19 = 7.5 x 10^20 J

E = 0.5mv^2

sqrt(2E/m) = v

but I'm getting something to x 10^23 so its obviously wrong.

its A-Level physics so shouldn't be a really complex answer...

Going wrong somewhere but can't work it out. Probably where I divided by the charge of an electron?

Any help appreciated.

James
 
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What exactly is an electronVolt?
 
You divided instead of multiplying. Try using dimensional analysis to convert from eV to Joules. It takes a lot of guess work out of the problem.
 
willem2 said:
What exactly is an electronVolt?

By definition, it is equal to the amount of kinetic energy gained by a single unbound electron when it accelerates through an electrostatic potential difference of one volt. (from Wiki)

efekwulsemmay said:
You divided instead of multiplying. Try using dimensional analysis to convert from eV to Joules. It takes a lot of guess work out of the problem.

Oh, my tutor told me to divide...

Is it because 1 Volt = 1 Joule/1 Coulomb

There for Joules = V * C ?

So eV multiplied but the charge of an electron give the Energy of the proton?

Also, I've not heard of Dinentional Analysis before, what exactly is it?

Thanks alot

james
 
So would the correct answer be...

120 * 1.6 x 10-19

= 1.92 x 10 -17

sqrt(2*1.92 x 10 -17/1.7 x 10-27) = v = 1.5 x 105 ms-1
 
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