What Torque Is Required to Raise a Water Bucket from a Well?

  • Thread starter Thread starter OierL
  • Start date Start date
  • Tags Tags
    Apply Torque
AI Thread Summary
To determine the torque required to raise a 20 kg water bucket from a well using a crank attached to a 50 kg cylinder, the relevant equations of motion and torque must be applied. The torque calculated for raising the bucket at a constant speed is approximately 24.5 N.m, which aligns with one of the provided options. The mass of the cylinder is not necessary for this calculation since the bucket is being raised at a constant speed, indicating no acceleration. The discussion highlights that the cylinder's mass may have been included to complicate the problem. Ultimately, the correct torque value is essential for selecting the appropriate answer from the given choices.
OierL
Messages
5
Reaction score
0

Homework Statement


Water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a cylinder of mass 50 kg and diameter 25 cm. As you turn this cylinder with a crank, the rope raises the bucket. If the mass of a bucket of water is 20 kg, what torque must you apply to the crank to raise the bucket of water at a constant speed?

Solution:
a. 2.5 N.m
b. 24 N.m
c. 80 N.m
d. 2400 N.m
e. 49 N.m
I don't know which one is the correct solution and why they give me the data of the weight of the cylinder.

Homework Equations


∑F=m*a
∑M=F*r and ∑M=I*α

The Attempt at a Solution


If we raise the bucket at a constant speed, ∑M=0
-m(bucket)*g + T=m*α*r=0 (constant speed) ⇒ T=m*g
∑M= (-T*R) + (τ)=0 (Being τ the torque I apply) ⇒ -(m*g*R) + τ=0 ⇒ τ= 20 * 9,8 * (0,25/2)
τ=24,5N*m
 
Physics news on Phys.org
Your answer looks fine. The mass of the cylinder will be needed if the bucket has a given acceleration different from zero.
 
Your solution looks good to me. The mass of the cylinder was just to throw you off.
 
Ok thank you! Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
 
OierL said:
Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
The choice should be clear.
 
OierL said:
Ok thank you! Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
That should not be too hard. Note that the numbers are given to two significant figures.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top