# Wheel Climbing a Step

1. Feb 17, 2008

### Carpe Mori

1. The problem statement, all variables and given/known data
a wheel of mass M has a radius R It is standing vertically on the floor and we want to exert a horizontal force F at its axle so that it will climb a step against which it rests. The step has a height h where h<R what is the minimum force F needed?

2. Relevant equations
torque = Ia
torque = FR

3. The attempt at a solution

Alrighty so i know that to solve this problem i will have to set the torque created by F equal to torque created by the weight of the wheel (Tf = Tw) and then solve for F but i honestly have no idea how to do this. There was another topic created for this problem but i could not follow what they did =\

2. Feb 17, 2008

### Staff: Mentor

There are only two forces to worry about: Find torques about the pivot point (where the wheel touches the step).

Start by drawing a diagram showing the forces and which way they act.

3. Feb 17, 2008

### Carpe Mori

http://i35.photobucket.com/albums/d185/giddyrayne/Picture018.jpg [Broken]

I understand torque = perpendicular force * radius

but it seems to me that the force's angle to the pivot point keeps changing.

Last edited by a moderator: May 3, 2017
4. Feb 17, 2008

### Staff: Mentor

True, but so what? You're asked to find the minimum force that would get it over the step. (At what point is the required force greatest?)

5. Feb 17, 2008

### Carpe Mori

When the torque due to gravity is not greater than the torque due to the force...or i guess the force just has to be equal to it sooo when Tf=Tw?

6. Feb 18, 2008

### Staff: Mentor

At any point, in order to just get the wheel over the step Tf=Tw. The required force will be greatest initially, since that's the point where Tw is greatest. That's all you need to consider to find the minimum force.