Why Am I Getting the Wrong Electric Field Intensity Calculation?

AI Thread Summary
The discussion revolves around a problem calculating the electric field intensity at a point in a rectangle with three point charges. The user applied the formula E = kq/r^2 to determine the electric field contributions from each charge, breaking down the components for one charge using trigonometric functions. Despite following the correct methodology, the user consistently arrives at an incorrect answer, which should be 6.93 * 10^3 at an angle of 78.8 degrees under the horizontal. Other participants in the thread suggest verifying the x and y components of the electric fields from each charge to identify potential errors in the calculations. The conversation emphasizes the importance of accurately determining the direction and magnitude of each component to solve the problem correctly.
bluntz48
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i have been stuck on this problem for days and can't figure out where I'm going wrong. i have a rectangle with sides 6cm and 8cm. 3 points of the triangle have a point charge on them with the following values:

q1 = -2 * 10^(-8) C
q2 = 8 * 10^(-8) C
q3 = -4 * 10^(-8) C

The point charges are arranged such that q1 is on top right, q2 on top left, q3 on bottom left. Find the field intensity at the 4th point (bottom right).

So what I did is use E = kq/r^2 (k = 9*10^9) to find the field intensity on the 4th point. For q2 I broke it into x- and y- components with E2x = E2 cos 36.87 and E2y = E2 sin 36.87. For q2 I found the angle of 36.87 by doing the inverse tan of 0.06/0.08 = 0.75 and i found the distance between the two points by using the pythagorean theorum (a^2 + b^2 = r^2).

Once I have both E1 and E3 as well as E2 broken into components, I add up the ones on the x-axis (E2x, E3) and the ones on the y-axis (E2y, E1). Then again I use the pythagoren theorum to add up the resultant (Ex^2 + Ey^2 = R^2)

I keep getting the wrong answer and I don't know why. Could you please point out where I'm going wrong or list the steps I should be taking so I could compare. The answer on the sheet is 6.93 * 10^3 at an angle of 78.8 under the horizontal

thanks everyone!
 
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bluntz48 said:
i have been stuck on this problem for days and can't figure out where I'm going wrong. i have a rectangle with sides 6cm and 8cm. 3 points of the triangle have a point charge on them with the following values:

q1 = -2 * 10^(-8) C
q2 = 8 * 10^(-8) C
q3 = -4 * 10^(-8) C

The point charges are arranged such that q1 is on top right, q2 on top left, q3 on bottom left. Find the field intensity at the 4th point (bottom right).

So what I did is use E = kq/r^2 (k = 9*10^9) to find the field intensity on the 4th point. For q2 I broke it into x- and y- components with E2x = E2 cos 36.87 and E2y = E2 sin 36.87. For q2 I found the angle of 36.87 by doing the inverse tan of 0.06/0.08 = 0.75 and i found the distance between the two points by using the pythagorean theorum (a^2 + b^2 = r^2).

Once I have both E1 and E3 as well as E2 broken into components, I add up the ones on the x-axis (E2x, E3) and the ones on the y-axis (E2y, E1). Then again I use the pythagoren theorum to add up the resultant (Ex^2 + Ey^2 = R^2)

I keep getting the wrong answer and I don't know why. Could you please point out where I'm going wrong or list the steps I should be taking so I could compare. The answer on the sheet is 6.93 * 10^3 at an angle of 78.8 under the horizontal

thanks everyone!

Sounds like your approach is right. The rectangle is 6 high by 8 wide?

Can you list the x and y components of E that you get for each of the 3 sources, so that we can check your math? E1 just points up, and E3 just points left, and E2 points down and to the right, correct?
 
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