Youngs Double Slit: Intensities at Maxima & Minima

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In a Young's double slit experiment with slit widths in the ratio of 1:2, the ratio of intensities at maxima and minima is determined to be 1:2. The discussion includes attempts to solve the problem and references to relevant equations and images for clarity. Participants express frustration over the lack of responses to the question. The correct answer has been confirmed as 1:2, indicating a clear understanding of the intensity distribution in this setup. This highlights the relationship between slit width and intensity in interference patterns.
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Homework Statement



In a youngs double slit experiment,if the slit widths are in the ratio 1:2,the ratio of intensities at maxima and minima will be ?

Homework Equations





The Attempt at a Solution


 
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You have to show us an attempt at solving the problem.
 
http://alt1.artofproblemsolving.com/Forum/latexrender/pictures/1/6/c/16cc24abee441abafab0b0e8aab86810683179b2.gif

http://alt1.artofproblemsolving.com/Forum/latexrender/pictures/1/1/1/1110014a64f5d6091d4bf58d3acf19dcd3197c52.gif

http://alt2.artofproblemsolving.com/Forum/latexrender/pictures/c/8/7/c877c1f06820a40e30df6abcdf2d4bab2bfac464.gif

http://alt1.artofproblemsolving.com/Forum/latexrender/pictures/6/8/e/68e2a20dfee135caf7a7d20e489b4b3a701ab961.gif

the correct answer is 1:2
 
Last edited by a moderator:
please answer
 
Cant anyone ans this?
 

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