Recent content by raddian

Can you please explain what are the correct equations for node A and B?

r I understand your point. Because the form tells me I have a decaying voltage, I need to have a negative argument to e. I need to apologize for not making my question very clear. I know the first form is correct (Node A) but is the second form equally valid but incorrect? And because they are...

My question applies to the case when the switch opens. By applying KCL in order to get a first order diff equation, the following problem arises when I choose different current directions (which shouldn't happen because KCL says the current direction doesn't matter because it will be fixed...

I am "continuing this thread" in hopes of asking questions that deal with the meaning of the question. https://www.physicsforums.com/threads/griffiths-e-m-3-33-write-e-field-of-dipole-moment-in-coordinate-free-form.359973/ 1. Homework Statement Show that the electric field of a "pure" dipole...

Oh so that's what face diagonals mean. :blushing: Thank you.

Isn't the line from (0,0,1) to (1,1,1) a face diagonal? The angle made with the edge and the inside diagonal is the angle of the face diagonal, assuming the face diagonal is (0,0,1) to (1,1,1), right?

Homework Statement Find the angle of the face diagonals of a (unit) cube. I agree with this solution, but I have a problem with another face diagonal: the face diagonal from the angle (0,0,1),(0,0,0), and (1,1,1). Homework Equations dot product cos-1(a.b/ (|a||b|) The Attempt at a Solution...

Thanks again!

Follow up question on using QUCS: I'm trying to make a current controlled voltage source matching this diagram...: Im not sure how exactly the current controlled voltage source is used in qucs.. Examples help, but I didnt know the right name for it in the examples given in qucs <Qucs...

I was able to find the Voltage between the open circuit using Thevenin and Node analysis: I got Vth = ~10.8 V (making Vy facing positive and Vx near negative), and Rth = 33/5. So the short circuit current is 10.8/6.6=1.6464 and current division between the load and 6.6 KOhms makes the load...

At first I didn't know what you meant by "driving the current through the 6 k "load" using whatever means you wish." but with FOIWATER's picture: I am able to understand now. Thank you! I will try my best to solve this using the techniques you suggested!

Homework Statement Find Io using Norton's Theorem Homework Equations The Attempt at a Solution I broke it into the following circuit: I would like to break it down some more but if I open the node between 3k and 6k (ohms), and 6k and 6k (ohms), I run into problems... What should I do to...

Homework Statement Find the gauge pressure of a piston-cylinder system, assuming that the piston perfectly covers the cylinder. The piston's radius is 5 cm, its mass is 3kg, and the force being applied to it is 75N in the same direction as gravity. Looks like this picture...

This gave me a new perspective. Thank you.

How would this statement apply to math and physics majors? Is it the discovery part that allows these scientists (or mathematicians) to fit society's needs? Aren't these majors learning in and of themselves? I said in my original post that I wanted to apply the knowledge.