How to Solve Tough Circuit Questions: Current, Power, and Graphing Tricks

  • Thread starter Thread starter scorpa
  • Start date Start date
  • Tags Tags
    Circuit Hard
Click For Summary
SUMMARY

This discussion focuses on solving complex circuit questions involving current, power, and graphing techniques. The user successfully calculated the current through R1 as 2.4 A and the total power dissipated in the circuit as 29 W. However, they struggled with determining the current through R4, which should be 0.8 A, and the power dissipated in R2, expected to be 5.1 W. Key strategies include applying Ohm's Law (V=IR) and understanding parallel resistor configurations.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of series and parallel resistor configurations
  • Familiarity with power formulas (P=IV and P=I²R)
  • Basic graphing skills for plotting resistance vs. cross-sectional area
NEXT STEPS
  • Study parallel resistor calculations in depth
  • Learn advanced circuit analysis techniques using Kirchhoff's laws
  • Explore power dissipation in resistors and its implications in circuit design
  • Review graphing techniques for electrical properties and their relationships
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone looking to enhance their problem-solving skills in circuit analysis.

scorpa
Messages
367
Reaction score
1
Hello there!

I am doing a really tough physics question on circuits. I am posting link to the picture of the circuit so you can actually see what is going on :smile:


These are the questions:

a) What is the current through R1?

This one was easy I just found the total resistance of the circuit and used the equation V= IR to get a current of 2.4 A which is the answer/

b) What is the current through R4?

I have no clue how to do this one, no matter what I do I get an answer either to high to to low. The answer should be 0.8 A.

c) What is the power dissipated in R2?


I have a feeling that I can't get this one because I can't get the one before it. The answer should be 5.1W.

d) What is the total power dissipated in the circuit?


I could do this one. It's just p = iv (12.0V)(2.4A) = 29W



Oh and one more really stupid thing. When you are drawing a graph and it says to plot resistance as a function of the cross-sectional area the resistance should go on the x-axis right? :redface:
 
Physics news on Phys.org
you've forgot the link
 



Hi there! Solving circuit questions can definitely be tough, but with a few tricks and techniques, you'll be able to tackle them with ease.

For question b), the key is to use Ohm's Law (V=IR) and the concept of parallel resistors. Since R2 and R3 are in parallel, they have the same voltage drop across them. This means that the current through R4 will be the same as the current through R2 and R3 combined. So, we can calculate the total resistance of R2 and R3 (1.5 ohms) and use that with the given voltage (12V) to find the total current through both resistors (8A). Since R4 is in series with this combination, the current through R4 will also be 8A. From there, you can use Ohm's Law again to find the voltage drop across R4, and then use that to find the current through R4 (0.8A).

For question c), you can use the same approach as question b) to find the current through R2 and then use power formula (P=I^2R) to find the power dissipated in R2.

And for the graphing question, yes, resistance should be on the x-axis since it is the independent variable.

Hope this helps and good luck with your circuit questions!
 

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
6K
Replies
22
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K