Hi, I read the following theorem in a book:
If {A_n} is a sequence of nowhere dense sets in a complete metric space X, then there exists a point in X which is not in any of the A_n's.
But what if I say X={1,1/2,1/3, ...} \cup {0} with the regular metric d(x,y)=|x-y|, and A_n={1/n,0}.
Why...