normalising \psi=|1,-1> is easy as \psi^*=<1,-1|
and then \psi^* \psi = <1,-1|1,-1>=2
which gives \psi= \frac{1}{\sqrt{2}} |1,-1> for the normalised ket.
but what about \psi=|1,-1>+2|0,0>+|-1,1>
i get \psi^*=<1,-1| +2<0,0| + <-1,1|
now I am guessing that seeing as i want to normalise...