Absolute Temperature and the Ideal Gas Law

AI Thread Summary
The discussion revolves around calculating the new temperature of air in a car engine cylinder after compression. Using the Ideal Gas Law, the initial conditions are set with a volume of 4.50 x 10^-2 m^3, a temperature of 30°C, and atmospheric pressure. The air is compressed to one-ninth of its original volume and twenty times the original pressure. The calculation leads to a new temperature of approximately 673 K, which is equivalent to 400°C. This demonstrates the relationship between pressure, volume, and temperature in gas behavior under compression.
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Homework Statement



A cylinder in a car engine takes Vi = 4.50 x 10^-2 m^3 of air into the chamber at 30°C and at atmospheric pressure. The piston then compresses the air to one-ninth of the original volume (0.111Vi) and to 20.0 times the original pressure (20.0 Pi). What is the new temperature of the air?

Homework Equations



P1V1/T1 = P2V2/T2

The Attempt at a Solution



I know I am supposed to convert my pressure and temperature to different numbers but I simply do not know what I am supposed to do. Please help!
 
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I figured it out.

(101 kPA)(.045 m^3)/303k = (2020 kPA)(.004995 m^3)/T2

673k or 400°C
 
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