Analysis of Functions I: increase, decrease, and concavity

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SUMMARY

This discussion focuses on analyzing functions to determine intervals of increase, decrease, concavity, and inflection points. The functions examined include f(x) = x^4 - 8x^2 + 16, f(x) = x/(x^2 + 2), and f(x) = x^2 ln(x). Key steps involve finding first and second derivatives, setting them to zero to identify critical points, and using the second derivative test for concavity. The second derivative for f(x) = x^4 - 8x^2 + 16 is f''(x) = 12x^2 - 16, which is solved to find inflection points.

PREREQUISITES
  • Understanding of first and second derivatives in calculus
  • Familiarity with the quotient rule for differentiation
  • Knowledge of solving polynomial equations
  • Ability to interpret concavity and inflection points
NEXT STEPS
  • Practice finding first and second derivatives for various functions
  • Learn to apply the second derivative test for concavity
  • Study the implications of critical points on function behavior
  • Explore advanced topics in calculus, such as optimization and curve sketching
USEFUL FOR

Students studying calculus, particularly those focusing on function analysis and critical point determination. This discussion is beneficial for anyone looking to strengthen their understanding of derivatives and concavity.

josh_123
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Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

Please help! Thank you!
 
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josh_123 said:
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16

So you need to solve the equation 12x^2-16 = 0. What is your problem?

josh_123 said:
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?

Use parentheses. The formula is wrong without them.
You will have a fraction. It can be zero if the nominator is zero.

josh_123 said:
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

To find x where the derivative is zero, factor out x.

ehild
 
josh_123 said:
Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
What? You don't know how to solve 12x^2- 16= 0? Add 16 to both sides, divide both sides by 12, then take the square root of both sides.

2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it?
you are taking Calculus and do not know how to solve equations like this? Multiply both sides of the equation by that denominator to get 2- x^2= 0

and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
Differentiate it, using the quotient rule again.

3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?
Oh, c'mon! 2xln(x)+ x= x(2ln(x)+ 1)= 0. One thing you surely learned long ago is that a product is equal to 0 only if one or more of the factors is 0. So here, either x= 0 or 2ln(x)+ 1= 0: x= 0 or ln(x)= -1/2.

and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?
2ln(x)+ 3= 0 leads to ln(x)=-3/2. Again, you should have learned in algebra or precalculus that if ln(x)= a then x= e^a. Once you know where it zero, you can determine the intervals in which the second derivative is positive or negative.

Please help! Thank you!
 
Actually I finished this before checking back haha. Please delete this post
 
Last edited:

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