Analysis of Functions I: increase, decrease, and concavity

josh_123
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Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

Please help! Thank you!
 
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josh_123 said:
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16

So you need to solve the equation 12x^2-16 = 0. What is your problem?

josh_123 said:
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?

Use parentheses. The formula is wrong without them.
You will have a fraction. It can be zero if the nominator is zero.

josh_123 said:
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

To find x where the derivative is zero, factor out x.

ehild
 
josh_123 said:
Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
What? You don't know how to solve 12x^2- 16= 0? Add 16 to both sides, divide both sides by 12, then take the square root of both sides.

2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it?
you are taking Calculus and do not know how to solve equations like this? Multiply both sides of the equation by that denominator to get 2- x^2= 0

and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
Differentiate it, using the quotient rule again.

3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?
Oh, c'mon! 2xln(x)+ x= x(2ln(x)+ 1)= 0. One thing you surely learned long ago is that a product is equal to 0 only if one or more of the factors is 0. So here, either x= 0 or 2ln(x)+ 1= 0: x= 0 or ln(x)= -1/2.

and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?
2ln(x)+ 3= 0 leads to ln(x)=-3/2. Again, you should have learned in algebra or precalculus that if ln(x)= a then x= e^a. Once you know where it zero, you can determine the intervals in which the second derivative is positive or negative.

Please help! Thank you!
 
Actually I finished this before checking back haha. Please delete this post
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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