Calculating Heat Required for Ice Cube Transformation

AI Thread Summary
To calculate the heat required to transform a 46.6 g ice cube from -12.5°C to water at 53°C, the correct specific heat capacities must be used. The calculations involve heating the ice, melting it, and then heating the resulting water. The specific heat of water is 4180 J/kg°C, not the specific heat of steam. The total heat calculation should include the correct values for each phase change and temperature increase, leading to a total heat requirement that differs from the initial incorrect total of 21792.723 J. Accurate application of the formulas and values is essential for the correct answer.
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How much heat is required to change a 46.6 g ice cube from ice at -12.5°C to water at 53°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C)

then i used Q=cmt and Q=mL

Q=(2090)(.0466)(12.5)=1217.425J
Q=(.0466)(33.5E4)=15611J
Q=(2010)(.0466)(53)=4964.298J

then when i add all the numbers up i get 21792.723J total but the answer is wrong. i don't know if I am using the formulas in the wrong order or what. I've done these problems in chemistry but its been a couple years since i took one of those courses. any help is appreciated.
 
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You use C_water, not C_steam for the last calculation (C_water is 4180)
 
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