Calculating Induced EMF in a Conducting Loop with Changing Magnetic Field

AI Thread Summary
To calculate the induced EMF in the conducting loop, use the equation for induced EMF, which is -dflux/dt, where flux is the product of the magnetic field B(t) and the area of the half circle. The magnetic field B(t) is given as a function of time, and you must add this induced EMF to the battery's EMF of 2.0V to find the total EMF in the loop. The direction of the induced EMF can be determined using Lenz's Law, which states that the induced current will oppose the change in magnetic flux. Finally, apply Ohm's Law (V = iR) to calculate the current in the loop at t = 10 seconds. Understanding these principles will help solve the problem effectively.
Moore65
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Here is a bonus question that I was given yesterday. I am completely at a loss of what to do. Any suggestions?

A conducting loop with a half circle of radius r=0.20m and 3 straight sections. The half circle lies in a uniform field B that is directed out of the page. The magnitude of B as a function of time is given by B(t) = 4.0t^2 + 2.0t + 3.0 where B is in Teslas and t is in seconds. An ideal battery with EMF E=2.0V is connected to the loop. The loop has a resistance of 2.0 Ohms.
a) Find the magnitude and direction of the EMF induced in the loop.

b) What is the current in the loop at t = 10 seconds?
 
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Moore65 said:
Here is a bonus question that I was given yesterday. I am completely at a loss of what to do. Any suggestions?

A conducting loop with a half circle of radius r=0.20m and 3 straight sections. The half circle lies in a uniform field B that is directed out of the page. The magnitude of B as a function of time is given by B(t) = 4.0t^2 + 2.0t + 3.0 where B is in Teslas and t is in seconds. An ideal battery with EMF E=2.0V is connected to the loop. The loop has a resistance of 2.0 Ohms.
a) Find the magnitude and direction of the EMF induced in the loop.

b) What is the current in the loop at t = 10 seconds?

just use the equation for induced emf: -dflux/dt.
flux = B(t)*area of half circle
add this emf as a function of time to the battery emf of 2.0V. I think you add, at least. they tell you the B field is directed out of the page, but they don't tell you which way the battery is connected... anyway, add 2 + (-dflux/dt) and this is your emf in the loop as a function of time. then use v = ir to calculate i(t).
 
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But how do I find the direction of the EMF?
 
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