Calculating Work and Input Force for a Hydraulic Lift

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AI Thread Summary
The discussion revolves around calculating the area of the input piston and the work done in lifting a 970-kg car using a hydraulic lift. The user seeks to find the area of the input piston using the relationship between input and output forces and areas. For the work done, the correct approach involves using the formula W = F * y, where F is the force required to lift the car and y is the height lifted. The force needed to lift the car is calculated as 970 kg multiplied by the acceleration due to gravity, resulting in approximately 1140.72 J for the work done. The user is encouraged to solve for the input piston area first to proceed with the calculations.
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Homework Statement



A hydraulic lift is used to jack a 970-kg car 12 cm off the floor. The diameter of the output piston is 18 cm, and the input force is 250 N. (A) What is the area of the input piston? (B) What is the work done in lifting the car 12 cm?

Homework Equations



Fo=mg m=mass of car g=gravity

Fi/Ai=Fo/Ao


The Attempt at a Solution



250N/Ai=mg/Ao

250N/x^2=mg/.18^2


Do I just need to solve for x to find solution "A". I am also having trouble getting started with "B", do I need to find "A" first?


Also, sorry if I posted this in the wrong spot. I am new to this and didn't really know how to go about posting. Thanks.
 
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I have start on "B"

W=(F2)(y)= ??

y=.12 m

Do I solve for F2?
 
jaco9115 said:
Do I just need to solve for x to find solution "A".

Since you used 0.18^2 on the other side of the equation and 0.18 is a diameter, the x in x^2 would also represent diameter.
I am also having trouble getting started with "B", do I need to find "A" first?

No. There's a very simple formula for the energy it takes to lift an object against gravity.
 
For "B"...would the simple formula be (970)(9.8)(.12)? therefore 1140.72 J correct?
 
Yup.
 
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