What Is the Area of the Largest Rectangle Inscribed in a Semicircle?

AI Thread Summary
The area of the largest rectangle inscribed in a semicircle with radius r is calculated using the formula A = r^2. To derive this, one can express one side of the rectangle in terms of the other, establishing a relationship between height and width. By drawing the semicircle and the inscribed rectangle, the dimensions can be analyzed to find the maximum area. The critical point is that knowing one dimension allows for the calculation of the other. Understanding these relationships is essential for solving the problem effectively.
thegame
Messages
32
Reaction score
0
What is the area of the largest rectangle that can be inscribes indiside a semicircle with the radius r?

answer: x = r / SQRT(2)
A = r^2
 
Physics news on Phys.org
Is there a question here?
 
How do you ge the answer?
 
How did YOU get the answer?
 
Well, if you know one side of a rectangle inscribed in a semicircle, can you figure out the other side?
 
What Hurkyl's getting at is:

Draw the semicircle. Draw a rectangle inside it, call one side h, call the other side w, call the radius r.

Now find a relationship that let's you eliminate either h or w. In other words, express h as a function of w, or w as a function of h.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top