Can I simplify this RLC circuit problem using a different method?

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Homework Help Overview

The discussion revolves around an RLC circuit problem involving the calculation of impedance and the determination of frequency values. The original poster expresses difficulty in simplifying the process of finding the maximum impedance and is exploring alternative methods to approach the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the modulus of the equivalent impedance and derive it with respect to frequency, but finds the resulting expressions overly complex. Some participants question whether there might be a simpler method or approximation that could be applied to the problem.

Discussion Status

Participants are actively engaging with the original poster's concerns, offering suggestions for clarity in the use of LaTeX and encouraging the sharing of detailed work to facilitate further assistance. There is an ongoing exploration of the problem's setup and potential simplifications, but no consensus has been reached on a specific method.

Contextual Notes

The original poster mentions constraints related to sharing images of their work due to a broken mobile phone, which may limit the clarity of their explanations. Additionally, there are references to specific values for components in the circuit, which may influence the calculations discussed.

Cloruro de potasio
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Homework Statement
Given the circuit of Fig. 13-6, with L = 4mH, C=2$\muF$, R1 = 25 ohms, R2 = 40 Ohms. Find the following set of frequencies.

a) where $\omega = 1/\sqrt{LC}$
b) where the impedance is maximum.
c) where the current through R1 is in phase with the generatori voltage.
Relevant Equations
Z = R + i(\omegaL - 1/\omegaC)

Series asociation of Z: $Z_eq = Z_1 + Z_2 + ...$
Association of Z in parallel: $Z_eq^-1 = Z_1^-1 + Z_2^-1 + ...$
Hello,

I have been thinking about this problem for a few hours, and I do not understand how I should proceed to solve it correctly. Section a is very simple, just substitute in the expression that gives us the values of L and C that the statement gives us.

However, when I get to section b, I have encountered the problem that what I have done is calculate the modulus of the equivalent impedance, and from there, try to derive with respect to $ \ omega $, in order to try to find the frequency value for which the impedance is maximum.

However, the expression of Z that remains is very long and complicated, both to calculate its module, and to derive, so I interpret that there must be another way to solve the exercise more easily, which has not occurred to me.

I leave you the figure on which the exercise deals, and the value of impedance that is obtained

Thank you very much in advance and regards
1588207879515.png

1588207928689.png
 
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Cloruro de potasio said:
Relevant Equations:: Z = R + i(\omegaL - 1/\omegaC)

Series asociation of Z: $Z_eq = Z_1 + Z_2 + ...$
Association of Z in parallel: $Z_eq^-1 = Z_1^-1 + Z_2^-1 + ...$

I leave you the figure on which the exercise deals, and the value of impedance that is obtained
No, please show your work where you did the algebra to calculate the Z for that simple circuit. Are you having trouble doing the algebra or dealing with the mix of complex impedances or keeping the parallel and series combinations straight? If you show your detailed work, we can try to help you figure it out.

Please use LaTeX when you post your math -- there is a tutorial at the top of the page under INFO/Help. Thank you. :smile:
 
Thanks again, the associations of impedances if I understand them correctly, and I know how to get to the expression that I have left above, the problem is that when calculating the module of the impedance, and deriving, the expressions that remain on very very long and ugly, and it is practically impossible, to clear the value of the requested frequency. Therefore, I have assumed that this is not the correct way to solve the exercise, I suppose that it will be necessary to make some approximation or some consideration that I cannot see, so that the problem is greatly simplified.

I have not uploaded your photos at work because I have a broken mobile phone, but I can try to ask someone to scan my pages
 
Cloruro de potasio said:
the problem is that when calculating the module of the impedance, and deriving, the expressions that remain on very very long and ugly, and it is practically impossible, to clear the value of the requested frequency.
The initial expression in the s-domain is not too bad, then substituting s=jω is not much worse, and then finding the real and imaginary parts is still not too bad, IMO. Finding the magnitude of the real part after that is a little messy, but necessary...
Cloruro de potasio said:
I have not uploaded your photos at work because I have a broken mobile phone, but I can try to ask someone to scan my pages
No pictures needed if you just read the LaTeX tutorial and start typing... :smile:
 
@Cloruro de potasio ,
I see that you did try to use ##LaTeX## to a small degree, particularly in the Homework Statement and Relevant Equations section of the Opening Post. A few tips for ##LaTeX## here at PF.

Rather than using a single $ for a delimiter, PF uses a double $ for stand alone expressions and a double # for inline expressions.

For your Homework Statement, you wrote
Given the circuit of Fig. 13-6, with L = 4mH, C=2$\muF$, R1 = 25 ohms, R2 = 40 Ohms. Find the following set of frequencies.

a) where $\omega = 1/\sqrt{LC}$
b) where the impedance is maximum.
c) where the current through R1 is in phase with the generator voltage.
Replacing each dollar sign ( $ ) with a double pound sign ( ## ) gives the following for the Homework Statement.

Given the circuit of Fig. 13-6, with L = 4mH, C=2##\mu F##, R1 = 25 Ohms, R2 = 40 Ohms. Find the following set of frequencies.

a) where ##\omega = 1/\sqrt{LC}##
b) where the impedance is maximum.
c) where the current through R1 is in phase with the generator voltage.

Similar modification to your Relevant Equations gives the following.

##Z = R + i(\omega L - 1/\omega C) ##

Series association of Z: ##Z_{eq} = Z_1 + Z_2 + ...##

Association of Z in parallel: ##Z_{eq}^{-1} = Z_1^{-1} + Z_2^{-1} + ...##

Added in Edit:
Note: That last line was entered as follows.
Association of Z in parallel: ##Z_{eq}^{-1} = Z_1^{-1} + Z_2^{-1} + ...## .
 
Last edited:
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