Can't make sense of this trig identity

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Homework Statement


im in first year differential calculas and i have no idea what my prof wrote down...i just copied it and thought ide figure it out later. but i can't fore the life of me.


Homework Equations


the identitie that he wrote is:

sinC+sinB=2Sin (C+D)/2 cos (c-D)/2


The Attempt at a Solution

 
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side note ) x+y = c
x-y = b
 


i understand where the sin C + sin B, its the (c+d)/2 that has me confused...these identities are just another way of writing the identities derived from adding and subtracting the addition and subtraction identities
 


Change the 'D' to 'B'. Then it works. Sure, it's derived from addition and subtraction identities. Basically everything is.
 


where did the (c+b)/2 come from...i know they subbed that in for x...but why?
 


I don't know, you didn't give us the whole problem. I do know sin(c)+sin(b)=2*sin((c+b)/2)*cos((c-b)/2).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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