Where Is the Center of Mass for Three Aligned Meter Sticks?

AI Thread Summary
To find the center of mass for three uniform meter sticks, the first step is to identify their positions: stick 1 is vertical along the y-axis, while sticks 2 and 3 are horizontal along the x-axis. Each stick has uniform mass, so the center of mass for each stick is at its midpoint. The overall center of mass can be calculated using the formula for weighted averages, taking into account the mass and position of each stick. The key challenge is correctly applying the formula to account for the distribution of the sticks in both the x and y dimensions.
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Homework Statement



Three uniform meter sticks, each of mass m, are placed on the floor as follows: stick 1 lies along the y-axis from y = 0.500 m to y = 1.50 m, stick 2 lies along the x-axis from x = 0.110 m to x = 1.11 m, stick 3 lies along the x-axis from x = 1.34 m to x = 2.34 m. Calculate the location of the center of mass of the meter sticks. Enter the x value first and then the y value.

Homework Equations



m1*y1+m2*y2.../m1+m2...

The Attempt at a Solution



this is the problem that i have to figure out. i know the equation for the center of gravity as being basically (m1y1+m2y2...)/m1+m2+... but since these are meter sticks and they all have the same weight yet take up more than one point on the system, i don't know where to go from here...can someone please help me?
 
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They are uniform sticks, so the center of mass is at the center of the stick.
 
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