I have to sleep sometime you know?!
Lets see - in reverse order:
if there are 10 trucks going in, do 5 of them have to go left and 5 go right. or can 1 go left and 9 go right?
How many trucks go in which direction depends on drivers and how difficult the path is. In terms of electrical currents, the exact current that ends up going in each direction depends on the resistances around the different paths - you get more current through the least resistance.
Is my equations for the current going through the nodes correct?
Dunno, I haven't checked. Remember, I'm not supposed to do your homework for you. When you understand what you are doing you'll be able to tell anyway.
also, I'm a bit confused on one of the loops.
You think there is only one voltage drop in loop 3? How can we check this? Let's walk around the loop - start at node B and go anti-clockwise (it's my favorite direction as I'm very sinister).
From B-C we encounter a 10 Ohm resistor whose arrow points against us (you forgot to draw the arrows on the resistors - they always point against the current) so that you get a factor of -10I
4 from this.
From C-B round the long way we come to another, unknown, resistor whose arrow is with us so this adds a factor of +RI
6 after which we end up back where we started. So we put an "= 0" on the end to give:
-10I
4 +RI
6 = 0
How many voltages was that? I make it two!
With three loops and four nodes you should have seven equations. The six currents and R make seven unknowns - so you have a system of simultaneous equations. Have fun.
You will probably find a current that is negative - this just means the arrow was drawn the wrong way around.