The discussion centers on calculating the coefficient of static friction (μs) for a crate with a mass of 275 kg on a 20.0° inclined plane. A horizontal force of 583 N is required to initiate movement down the incline. The correct formula for μs is derived as μs = (w sin ∅ + 583 cos ∅) / (w cos ∅ - 583 sin ∅), correcting the initial assumption that the normal force remains constant at mg cos θ. The final calculated coefficient of static friction is confirmed to be 0.630.
PREREQUISITESThis discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces on inclined planes, particularly in relation to static friction calculations.
You are assuming that the normal force remains mgcosθ, but the presence of the horizontal force changes that. Also, what's the component of that horizontal force parallel to the surface?EliteLennon said:U = (((mg sin (∅)) + (583 cos (70)) / (mg cos (∅))
Doc Al said:You are assuming that the normal force remains mgcosθ, but the presence of the horizontal force changes that. Also, what's the component of that horizontal force parallel to the surface?