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Homework Help Overview

The discussion revolves around the relationship between polarization and magnetization vector fields and their connection to the electric displacement field (D), electric field (E), magnetic field (B), and magnetic field intensity (H). Participants are exploring foundational concepts in electromagnetism.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to relate the equations for D and H to polarization (P) and magnetization (M). Questions arise regarding the correct use of constants and the implications of assumptions made about permittivity and permeability.

Discussion Status

Some participants are sharing their thought processes and equations, while others provide feedback on the use of specific constants. There is a collaborative effort to clarify the relationships between the various vector fields, though no consensus has been reached on the interpretations or methods.

Contextual Notes

There are indications of confusion regarding the appropriate constants to use in the equations, as well as assumptions about the limits of permittivity and permeability. The discussion reflects a common challenge in understanding the interplay of these concepts in electromagnetism.

ParticleGinger6
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Homework Statement
Maxwell's Equation in matter reduces to Maxwell's equation in vacuum if polarization and magnetization are zero?
Relevant Equations
They can be found in the attached photo
I do not know where to start.
 

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How are polarization (i.e. the Polarization Vector Field) and magnetization (i.e. Magnetization Vector Field)\\ related to the vector fields \vec D , \vec E, \vec B, and \vec H?
 
@robphy so i found the equations D = epsilon*E and H = (1/mu)*H where epsilon = epsilon(not)*(1+Xe) and mu = mu(not)*(1+Xe). I think if I use that convert D into terms of P which would look like P = D - epsilon(not)*E and H = B/(mu(not)*(1+Xe)). From there you can get Magnetization from M = Xm*H

Am I on the right track
 
Yes... but use \epsilon_0 and \mu_0 instead of the \chis.
 
@robphy I believe I figured it out. So by using D = epsilon(not)E + P and H = B/mu(not) - M I was able to get to
dell * E = rou/epsilon(not) and dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t) for part a
Then for part b
I used P = epsilon(not)*X*E to get dell*E = rou/epsilon(not)
I used M = Xm*H to get dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t)
Both assuming mu approaches mu(not) and epsilon approaches epsilon(not)
 

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