Cuttoff frequwncy for an x-ray tube

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To calculate the cutoff frequency of an x-ray tube operating at 44kV, the formula used is frequency = work function/h. The user initially converted kV to eV but made an error in the value of Planck's constant. Correcting the value of Planck's constant from 1.626E-34 to 6.626E-34 resolved the issue. This highlights the importance of accurate constants in calculations. The discussion emphasizes the collaborative nature of problem-solving in physics.
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How would you calculate the cutoff frequency of an x-ray tube operating at 44kV? I am using frequency = work function/h. I have (44000eV x 1.602E-19J)/1.626E-34 but my answer is wrong. I'm thinking that I converted kV to eV incorrectly, but I'm not sure.
Thanks.
 
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ladiebug511 said:
How would you calculate the cutoff frequency of an x-ray tube operating at 44kV? I am using frequency = work function/h. I have (44000eV x 1.602E-19J)/1.626E-34 but my answer is wrong. I'm thinking that I converted kV to eV incorrectly, but I'm not sure.
Thanks.

Your value for Planck's constant is wrong (that 1 should be a 6). Does that fix it?
 
hage567 said:
Your value for Planck's constant is wrong (that 1 should be a 6). Does that fix it?

Yes. Thanks for pointing out my stupid mistake :) Sometimes it just takes a fresh set of eyes.
 

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