Damped Driven Harmonic Oscillator.

Click For Summary

Homework Help Overview

The discussion revolves around a damped driven harmonic oscillator characterized by specific parameters including mass, stiffness, mechanical resistance, and a sinusoidal driving force. Participants are tasked with plotting speed amplitude and phase angle as functions of driving frequency, specifically identifying frequencies where the phase angle is 45 degrees.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the general solution for the oscillator and questions whether the phase angle between displacement and speed is consistently π/2 across frequencies. Other participants clarify the distinction between phase shifts related to driving force and displacement.

Discussion Status

The conversation is exploring the interpretation of phase relationships in the context of the problem. Some participants express agreement on the need for clarification regarding the phase angle, while others suggest it may be a misprint in the problem statement. No consensus has been reached, but the discussion is actively engaging with the problem's nuances.

Contextual Notes

Participants are considering the possibility of a misprint in the problem statement regarding the phase angle, which may affect their interpretations and solutions.

vkumar1403
Messages
3
Reaction score
0

Homework Statement


An oscillator with mass 0.5 kg, stiffness 100 N/m, and mechanical resistance 1.4 kg/s is driven by a sinusoidal force of amplitude 2 N. Plot the speed amplitude and the phase angle between the displacement and speed as a function of the driving frequency and find the frequencies for which the phase angle for which the angle is 45 deg.

Homework Equations

The Attempt at a Solution


Using the general form of the solution:
x(t) = A(w) sin(wt-Φ)
where Φ=atan(2wp/(w_0^2-w^2))
A(w) = (F/m)/((w_0^2-w^2)^2 + (2wp)^2)^0.5

I am positive the above equations are correct and come from the differential equation for this case.

Now, u(t) [speed] = d x(t)/dt.
= w*A(w)*cos(wt-Φ)
=w*A(w)*sin(wt-Φ+pi/2)

My question: Now the speed amplitude, I believe, is wA(w). Won't the phase angle between the displacement and velocity always be pi/2 irrespective of w?[/B]
 
Physics news on Phys.org
Yes, but this is not the phase shift. The phase shift is the phase between the driving force and the position, i.e., φ.
 
Orodruin said:
Yes, but this is not the phase shift. The phase shift is the phase between the driving force and the position, i.e., φ.
I agree but the question says the phase between the speed and the displacement. Am I interpreting this wrong?
 
vkumar1403 said:
I agree but the question says the phase between the speed and the displacement. Am I interpreting this wrong?
It is very likely a misprint.
 
Orodruin said:
It is very likely a misprint.
Thanks! I'm going to quote this as a misprint in my solution with the explanation of my rationale. Hopefully, that is good enough for my professor
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
9
Views
2K
Replies
7
Views
1K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
3
Views
895
Replies
5
Views
1K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K