Double integral with polar coordinates

Mathoholic!
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Homework Statement


It is given a set defined as: 0≤x≤1, 0≤y≤1-x. With x,y in ℝ.

f(x,y)=1 (plane parallel to Oxy plane)

They ask you to express the integral ∫∫Setf(x,y)dxdy in polar coordinates and calculate it.


Homework Equations



x=rcosθ
y=rsenθ
r=√x2+y2

The Attempt at a Solution



I've done the variable substitution as:

0≤rcosθ≤1, 0≤rsenθ≤1-cosθ and ∫∫Setrdrdθ

After analysing it for a bit I figured that 0≤r≤1 and that 0≤θ≤\frac{\pi}{2}.
However, the solution to the integral is 0.5. For the limits I've established, it gives me \frac{\pi}{4}.

I can easily calculate that integral in x,y coordinates but I'm having trouble defining the endpoints of r and θ when changing a set from x,y coordinates to r and θ coordinates.

Can you help me with this?
 
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Mathoholic! said:

Homework Statement


It is given a set defined as: 0≤x≤1, 0≤y≤1-x. With x,y in ℝ.

f(x,y)=1 (plane parallel to Oxy plane)

They ask you to express the integral ∫∫Setf(x,y)dxdy in polar coordinates and calculate it.


Homework Equations



x=rcosθ
y=rsenθ
r=√x2+y2

The Attempt at a Solution



I've done the variable substitution as:

0≤rcosθ≤1, 0≤rsenθ≤1-cosθ and ∫∫Setrdrdθ

After analysing it for a bit I figured that 0≤r≤1 and that 0≤θ≤\frac{\pi}{2}.
However, the solution to the integral is 0.5. For the limits I've established, it gives me \frac{\pi}{4}.

I can easily calculate that integral in x,y coordinates but I'm having trouble defining the endpoints of r and θ when changing a set from x,y coordinates to r and θ coordinates.

Can you help me with this?

##r## doesn't go from 0 to 1. In your picture, pick some ##\theta## and draw the ##r## for that ##\theta##. ##r## goes from 0 to the ##r## value on the line. So write the equation of the line in polar coordinates and solve it for ##r##. That is your upper limit on ##r##.
 
What's senθ? :smile:

Using your given limits for x and y, you should draw the graph, so you can understand and derive the limits for polar coordinates.
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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