Downward Projectile Motion on an Inclined Plane

AI Thread Summary
The discussion revolves around calculating the landing velocity of a skateboarder launching from a ramp on an inclined plane. The skateboarder leaves the ramp at a height of 1.4 m, with an initial speed of 15 m/s at a 40° angle, while the slope is inclined at 45°. Participants express uncertainty about incorporating the ramp height into the calculations and finding the final velocity, particularly due to the two components of motion involved. Suggestions include using parametric equations to represent the projectile's trajectory and the slope, allowing for the determination of their intersection point. This approach aims to clarify the relationship between the skateboarder's motion and the inclined plane.
dakota224
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Homework Statement


A skateboarder in a death-defying stunt decides to launch herself from a ramp on a hill. The skateboarder leaves the ramp at a height of 1.4 m above the slope, traveling 15 m/s and at an angle of 40° to the horizontal. The slope is inclined at 45° to the horizontal. With what velocity does the skateboarder land on the slope?

skateboard.png


Homework Equations


tanФ = -y/x
x=x0+v0cosθt
y=y0+v0sinθt-(1/2)gt2

The Attempt at a Solution


BD33A846-E142-4B4E-B293-E051532A0C82.JPG

I am really not sure how to go about this, especially how to incorporate the height of the ramp. I have not found any sample problems like this one, as they all seem to have the object shooting up the hill from flat ground rather than shooting down off a ramp, or similar ski jump problems do not account for ramp height. In addition, I'm not sure how to find a final velocity at the end - won't I have two components of velocity?
 
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dakota224 said:

Homework Statement


A skateboarder in a death-defying stunt decides to launch herself from a ramp on a hill. The skateboarder leaves the ramp at a height of 1.4 m above the slope, traveling 15 m/s and at an angle of 40° to the horizontal. The slope is inclined at 45° to the horizontal. With what velocity does the skateboarder land on the slope?

View attachment 97142

Homework Equations


tanФ = -y/x
x=x0+v0cosθt
y=y0+v0sinθt-(1/2)gt2

The Attempt at a Solution


View attachment 97143
I am really not sure how to go about this, especially how to incorporate the height of the ramp. I have not found any sample problems like this one, as they all seem to have the object shooting up the hill from flat ground rather than shooting down off a ramp, or similar ski jump problems do not account for ramp height. In addition, I'm not sure how to find a final velocity at the end - won't I have two components of velocity?
I notice that I plugged in 14º and not 40º for the ramp angle right off the bat, but the answer would still be incorrect.
 
See if you can't turn it into a problem of an intersection of two functions. The typical equations of motion for projectile motion, where the x and y components are treated as separate functions of time, are just the equation of the trajectory in parametric form (the "parameter" being time t).

If you can write the trajectory in the form y(x) = <some function of x>, and the equation of the slope in the same fashion, then you should be able to find their points of intersection.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
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