Efficient Integration of Exponential Functions with Infinite Limits

ronaldoshaky
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Homework Statement



how would you integrate, int (-ik - 2ax)*exp(-2ax^2) dx with limits infinity - infinity

Homework Equations



i think i can use the result int exp(-x^2) dx = sqrt (pi). But I am stumped.

The Attempt at a Solution



i thought about multiplying it out

int -ik*exp(-2ax^2) - 2ax*exp(-2ax^2) dx with limits infinity and - infinity

but it looks more complex now. would you use integration by substitution

Thank you
 
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Welcome to PF!

Hi ronaldoshaky! Welcome to PF! :smile:

(have an integral: ∫ and an infinity: ∞ and a pi: π and try using the X2 tag just above the Reply box :wink:)

Just do the two parts separately …

-∞ ik e-2ax2 dx you know how to do;

and ∫ 2ax e-2ax2 dx you can do by substitution. :wink:
 
Thank you!
 
Hi tiny-tim

Can I evaluate this integral ∫-∞∞ (ik-2ax) exp(-2ax2) dx without multiplying it out,
using integration by parts because it is a product?

I get


∫-∞∞ (ik-2ax) exp(-2ax2) dx = f(x)g(x) - ∫ f '(x)g(x) = - ik (sqrt (pi/2a)) + ikx (sqrt (pi/2a))

Is that any way correct?
 
No. :redface:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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