Electric dipole in an electric field

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SUMMARY

The discussion focuses on the behavior of an electric dipole in a uniform electric field, specifically its motion when slightly displaced from equilibrium. The derived frequency of simple harmonic motion is given by the formula f = (1/2π)√((2qE)/(m1 + m2)a). The participants clarify the importance of the moment of inertia in relation to the dipole's rotation about a fixed axis versus its center of mass. The correct interpretation of the dipole's motion is crucial for accurate calculations.

PREREQUISITES
  • Understanding of electric dipoles and their properties
  • Familiarity with simple harmonic motion concepts
  • Knowledge of rotational dynamics and moment of inertia
  • Basic proficiency in calculus for differential equations
NEXT STEPS
  • Study the derivation of the moment of inertia for different rotational axes
  • Explore the principles of simple harmonic motion in electric fields
  • Learn about the dynamics of electric dipoles in varying electric fields
  • Investigate the applications of electric dipoles in real-world scenarios
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Physics students, educators, and researchers interested in electromagnetism, particularly those studying the dynamics of electric dipoles and their applications in various fields.

vladimir69
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Homework Statement


An electric dipole (something that has charge +q on one end and charge -q on the other end separated by a distance 2a) is in a uniform horizontal electric field of magnitude E. Initially the electric dipole is aligned horizontally until it is displaced slightly by an angle theta from the horizontal. Show that the electric dipole undergoes simple harmonic motion with frequency given by
f=\frac{1}{2\pi}\sqrt{\frac{(m_{1}+m_{2})qE}{2m_{1}m_{2}a}}


Homework Equations


I\alpha=\tau_{net}
\omega=2\pi f
F=qE
\theta(t)=A\cos(\omega t)

The Attempt at a Solution


Here is what I got
I=(m_{1}+m_{2})a^2
(m_{1}+m_{2})a^2\frac{d^2\theta}{dt^2}\approx 2aqE\theta
and the frequency I get pops out as
f=\frac{1}{2\pi}\sqrt{\frac{2qE}{(m_{1}+m_{2})a}}
Can't see where I have gone wrong
 
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See the units: the given formula can not be correct. Yours is all right.

ehild
 
I thought the units were ok in both the equations
 
Yes, you are right, I misread the formula somehow...

The question is if the dipole rotates around a fixed axis through its centre, so both masses are at a distance "a" from the axis of rotation or it is free and then it rotates around its CM.
In case of the first situation, your formula is right. The formula given by your book is valid for the free dipole. In this case you need the moment of inertia with respect to the CM.

ehild
 
Ok I see now, thanks for your help.
 

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