Electric Field in a Wire (Concepts)

AI Thread Summary
The electric field inside a wire is inversely proportional to the resistivity of the material and directly proportional to the current passing through the wire. Ohm's Law can be applied to relate these concepts, specifically using the equations V=IR and J=σE, where J is current density and σ is conductivity. The discussion highlights the importance of understanding these relationships to solve related problems. The user successfully finds the answers to their homework questions with this information. Overall, the thread emphasizes the connection between electric field, resistivity, and current in conductive materials.
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Homework Statement



A) [Directly proportional/Inversely proportional] The electric field inside the wire is ... to resistivity of the material the wire made of.

B) [Directly proportional/Inversely proportional] The electric field inside the wire is ... to the current passing through the wire.

Homework Equations


This is my problem, I can't seem to find any equations that relate electric field to the resistivity or current in the wire.

The Attempt at a Solution


My guess is that A is inversely proportional, and B is directly proportional but its just a guess.
 
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Ohm's Law comes in two forms. The form more common to intro physics is:

V=IR

The other form is the following:

J=\sigma E where J is the current density and sigma is the conductivity (inverse of resistivity).

Can you use these equations to answer the questions?
 
Thanks GO1! Thats exactly what i was looking for. I've got the answers now :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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