Electric Fields and Kinetic Energy of protons

AI Thread Summary
To determine the electric field required to stop protons with a kinetic energy of 3.25 x 10^-15 J over a distance of 1.25 m, the work done by the electric force must equal the change in kinetic energy. The initial kinetic energy is provided, while the final kinetic energy is zero since the protons come to a stop. The relationship between force, electric field, and charge is utilized, where the electric field is calculated as the force divided by the charge of the protons. The relevant equations involve the concepts of work, kinetic energy, and electric force. The solution involves calculating the necessary electric field magnitude and direction to achieve this stopping distance.
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Homework Statement



Each of the protons in a particle beam has a kinetic energy of 3.25 x 10^-15 J. What are the magnitude and direction of the electric field that will stop these protons in a distance of 1.25 m?


Homework Equations



Felectric = kC (q*q/r^2)
Electric Field= Felectric/q
Electric Field= kC (q/r^2)
Velocityfinal= velocityInitial + a*t
Velocityfinal^2 = VelocityInitial^2 + 2a(d)



The Attempt at a Solution



I need help with this.
 
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Work done by the electric force = change in the KE.
Initial KE is given. Final KE = ...?
Work done by the electric force F = ...?
And as you have stated E = f/q.
Now try.
 
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