Calculating Electric Flux Through a Non-Uniform Hemispherical Surface

AI Thread Summary
To calculate the electric flux through a non-uniform hemispherical surface with a point charge at the origin, the solid angle method is deemed inappropriate due to the non-uniform electric field. Participants suggest focusing on the flux through the equatorial area of the hemisphere. The challenge lies in determining how to calculate this flux effectively, given the varying distances from the charge to different points on the surface. The discussion highlights the need for a clear approach to integrate the electric field over the specified area. Overall, the conversation centers on finding a suitable method to compute the electric flux in this specific geometry.
Abhishekdas
Messages
198
Reaction score
0

Homework Statement


A point charge is placed at the origin. Calculate the electric flux through the open hemispherical surface :(x-a)2 +y2 + z2 = a2
x> or = a.



Homework Equations





The Attempt at a Solution


There is no diagram but this is how i visualised the question(please refer to attachment)...
Now i was thinking of proceeing via solid angle method but it won't work here i guess because each point on the spere is not equidistant from the charge so the field isn't uniform...So how to go about it?
 

Attachments

Physics news on Phys.org
Hi Abhishekdas! :smile:

Just find the flux through the "equator". :wink:
 
Hi tiny-tim...

I think you mean to say flux through the area bounded by the equator...
But how do i find that...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Flux through a cylindrical surface enclosing part of a sphere
Replies
9
Views
550
Calculating flux through a plane cutting two concentric cylinders
Replies
26
Views
1K
Electric flux through ends of an imaginary cylinder
Replies
7
Views
2K
Electric Flux through Cubical Surface Enclosing Sphere
Replies
2
Views
4K
Electric Flux Through Spherical Surface Centered at Origin
Replies
3
Views
4K
Electric flux through a hemisphere due to these charge configurations
2
Replies
51
Views
7K
Flux of Electric Field through a cone
Replies
3
Views
2K
How Is Electric Flux Calculated for a Rectangle in an Electric Field?
Replies
5
Views
2K
Electric Flux through the Face of a Cube
Replies
17
Views
8K
Flux Through a Cube's Face with our Point Charge at a Corner
Replies
6
Views
4K

Hot Threads

Recent Insights

Back
Top