How Do You Calculate Electrostatic Force Between Charges?

AI Thread Summary
To calculate the electrostatic force between two positive point charges, the Coulomb's law formula must be applied correctly, considering both magnitude and direction as vector quantities. The charges are positioned at different y-coordinates, and the charge being evaluated is on the x-axis, which affects the distance calculations. The initial attempt to sum forces as scalars was incorrect; the vector nature of forces requires proper vector addition, including consideration of y-components. Additionally, the discussion touches on the nature of electrostatic interactions, questioning the speed of these interactions and the existence of a messenger particle, likely referring to the concept of virtual photons in quantum field theory. Understanding these principles is crucial for accurately determining the resultant force in electrostatic scenarios.
BoldKnight399
Messages
78
Reaction score
0
Two positive point charges, each of which
has a charge of 1.5 × 10−9 C, are located at
y = +0.50 m and y = −0.50 m.
The Coulomb constant is 8.98755 ×
10^9 N · m2/C2.
a) Find the magnitude of the resultant elec-
trical force on a charge of 1.0×10−9 C located
at x = 0.55 m.
Answer in units of N.

So I drew out a force diagram and thought that the equation would be:
Fel=kc(Q1*q/d1^2)+kc(Q2*q/d2^2) where the q is the 1.0e-9C charge.
Fel=(8.98755e9)(1.5e-9*1.0e-9/.0025)+(8.98755e9)(1.5e-9*1.0e-9/1.1025)
so Fel=5.404757e-6

Apparently that was the wrong answer. Does anybody know or want to explain how I should now re-examine the problem?
 
Physics news on Phys.org
The force from each charge is a vector. You have to add them like vectors, not numbers--the direction matters. Hint: What happens to the y-components?

Also: What's the distance between the charges?
 
yeah...I missed the fact that q was on the x axis. makes sense now. Thank you for your help!
 
I have a question about the operation of the electrostatic force. I solved the Maxwell's equations in a pure static electric conditions and the result I got does not look like a wave equation. If that is the case, then what is the speed of electrostatic interaction in free space? And what is the messenger particle?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top