Entropy Difference of an Unknown Gas (not an ideal gas)

AI Thread Summary
The discussion revolves around estimating the entropy difference S2-S1 for an unknown gas under specific conditions. The participants clarify that state 3 can be ignored since the focus is on the transition between states 1 and 2, which involves a compression process where volume decreases and pressure increases while temperature remains constant. They explore the relationship between entropy, pressure, and volume, referencing Maxwell's equations to derive the necessary equations. The key equation discussed is -(∂S/∂P)T=(∂V/∂T)P, which allows for estimating the entropy change using finite differences. The consensus is that this approach is valid for the estimation required in the homework problem.
albertov123
Messages
21
Reaction score
1

Homework Statement


Temperature, pressure and volume measurements performed on 1 kg of a simple compressible substance in three stable equilibrium states yield the following results.

State 1 (T1=400 C , V1= 0,10 m3, P1=3 MPa)
State 2 (T1=400 C , V1= 0,08 m3, P1=3,5 MPa)
State 3 (T1=500 C , V1= 0,10 m3, P1=3,5 MPa)

Estimate the difference in entropy S2-S1

Homework Equations


We don't know the gas. So I can't assume this is an ideal gas and I can't go to thermodynamics tables. I don't know the relevant equation.

The Attempt at a Solution


First, I didn't get why the question identifies state 3. I think we can completely ignore state 3 because the question is entropy difference between state 2 and state 1.

This is clearly a compression process, (volume decreases, pressure increases) but temperature stays still. But when a gas is compressed, its pressure and temperature rises. So there must be heat transfer going on.

Entropy change = Sgen + Q/T
But we don't know the entropy generation so we can't go from here.

I assume I need a relation related with volume and pressure that yields entropy but in constant temperature. Is there a relation like that?
 
Physics news on Phys.org
Yes. There is a relation for the partial derivative of entropy with respect to pressure at constant temperature in terms of the P-V-T properties of a gas.
Have you studied that yet? Are you learning about the Maxwell equations in your course yet? The derivation starts off with dG=-SdT+VdP.
 
  • Like
Likes albertov123
Yes we are learning maxwell equations in fact. That derivation must be dG=-SdT+VdP+∑μidNi from my notebook.

The relation you have mentioned is probably -(∂S/∂P)T=(∂V/∂T)P and with that equation my solution would include state 3. But how could i go with this equation I'm not clear. Although I'm very doubtful, can I think the above equation as -(ΔS/ΔP)between state 1-2=(ΔV/ΔT)between state 2-3? Otherwise I don't know what to do.
 
Albertov123 said:
Yes we are learning maxwell equations in fact. That derivation must be dG=-SdT+VdP+∑μidNi from my notebook.

The relation you have mentioned is probably -(∂S/∂P)T=(∂V/∂T)P and with that equation my solution would include state 3. But how could i go with this equation I'm not clear. Although I'm very doubtful, can I think the above equation as -(ΔS/ΔP)between state 1-2=(ΔV/ΔT)between state 2-3? Otherwise I don't know what to do.
Yes, that's what you do. They said "estimate" the entropy change, so using finite differences is OK.
 
  • Like
Likes albertov123

Similar threads

Back
Top