A 8.20-kg block of ice, released from rest at the top of a 1.43-m-long frictionless ramp, slides downhill, reaching a speed of 2.11 m/s at the bottom. What is the angle between the ramp and the horizontal? What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of 11.0 N parallel to the surface of the ramp? I think I use the equations of ax=gsin(theta) and Fn=mgcos(theta)? I'm not sure what to do. Can someone please help me? Thank you!