Find Mass of Radioactive Sample Given MeV & Bq

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To find the mass of a radioactive sample given its energy in MeV and decay rate in Bq, the relationship between energy and mass can be utilized through the equation E=mc^2, with energy converted from eV to joules. If the sample is stationary, this method applies directly, while moving samples require additional considerations. The decay rate, often represented by the decay constant (lambda), needs clarification as the term "Bq" may not be universally understood. The discussion highlights the importance of using the correct formulas to avoid losing marks in academic settings. Understanding these relationships is crucial for accurate calculations in radioactive decay studies.
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I wanted to know how to find the mass of a radioactive sample given its Energy "MeV" and and decay rate "Bq"?
Can you please give me a hand with this one by giving me the formula.

Please don't solve an example because this is part of my case study.

Thanks alot
:wink:
 
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Some details: is the radioactive object moving? If not, then it's energy (in eV) corresponds to its mass using a certain well-known equation (E=mc^2). BUt in order to get kg, you need to convert eV to joules (1eV = 1.602 x 10^-19 joules).
If the radioactive sample is moving then you need to do a little more.

I'm not familiar with decay rate as "Bq." Usually the decay constant is represented by a greek "lambda." Could you specify what the B and the q represent?
 
thanx

I thought there was a harder way.

i had that in mind but usualy what i think at the end i might get the same answer but since the formula is diffrent i lose marks.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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