Find postition on third charge question

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To find the position for a third charge of 3.11E-9 C so that the net electrostatic force on it is zero, it is essential to consider the repulsive forces between all three positive charges. The discussion emphasizes that placing the third charge to the left of the other two would not yield a net force of zero, as both existing charges would repel it. Instead, the third charge must be positioned between the two existing charges or to the right, where the forces can balance out. Participants are encouraged to think critically about the directions of the forces acting on the third charge. Ultimately, understanding the nature of electrostatic forces is key to solving the problem effectively.
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Find postition of third charge question

Homework Statement


A charge of 1.57E-9 C is placed at the origin, and a charge of 4.23E-9 C is placed at x = 1.51 m. Find the position at which a third charge of 3.11E-9 C can be placed so that the net electrostatic force on it is zero.

Please help me out with this one


Homework Equations





The Attempt at a Solution

 
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First question: Given that the charges are all positive, and that positive charges repel, do you think the 3rd charge should be placed to the left of both charges, to the right of both charges, or inbetween the two charges? Why?
 
Tom Mattson said:
First question: Given that the charges are all positive, and that positive charges repel, do you think the 3rd charge should be placed to the left of both charges, to the right of both charges, or inbetween the two charges? Why?

i guess it would be at the left of the two charges to counter them..i guess
 
Don't guess. Think.

If the 3rd charge were to the left of the other two, and the other two were both repelling it, then is it even possible that the net force on the 3rd charge is zero? Think about the directions of the forces on the 3rd charge.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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