Find the equivalent resistance in a circuit

AI Thread Summary
The discussion revolves around calculating the equivalent resistance in a circuit with multiple resistors. Two 4 Ohm resistors are identified as being in series, resulting in an 8 Ohm total resistance. The remaining resistors, 2 Ohm, 4 Ohm, and 2 Ohm, are confirmed to be in series as they carry the same current. This leads to the conclusion that the two 8 Ohm resistors are in parallel, yielding a net resistance of 4 Ohms. The solution can be verified using Kirchhoff's law to confirm that the current in both branches is the same.
jakobsandberg
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Homework Statement



Find the equivalent resistance in the circuit below:

circuit.jpg


Homework Equations



The Attempt at a Solution



I know the two 4 Ohm resistors (on the same wire) are in series and thus add to 8 Ohms. However, I do not know where to go from here. When the resistors are in a box, with one on each side, are they in series? Or are they two parallels?

Thanks!
 
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I believe the 2,4,2 ohm resistors are all in series since the same current flows through them.
 
rock.freak667 said:
I believe the 2,4,2 ohm resistors are all in series since the same current flows through them.

So this would leave me with two parallel resistors of 8 Ohms each? And finding the equivalent resistance would give us 4 Ohms?

If you (or someone else) can confirm this, it would be greatly appreciated!
 
yep. 8 ohm 8ohm are in parrellel giving 4 ohm net resistance. can be veryfied using kirhoff's law to show current in both branches are the same.
 

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