Finding the Electric Field given the potential in spherical

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The discussion revolves around calculating the electric field from a given potential using the equation E = -∇φ. Participants express confusion about taking derivatives in spherical coordinates, particularly regarding the variable nature of r. One suggestion is to switch to Cartesian coordinates for clarity, utilizing specific partial derivatives to simplify the process. There is a debate on whether substituting r directly leads to correct results, with participants questioning their understanding of vector calculus. The conversation highlights the complexities of deriving electric fields from potentials in different coordinate systems.
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Homework Statement


The problem statement is in the attachment

Homework Equations


E[/B] = -φ

= (∂φ/∂r)er

The Attempt at a Solution



I am confused about how to do the derivative apparently because the way I do it gives

E = - (∂[p*r/4πε0r3]/∂r)er = 3*(p*r)/4πε0r4er
 

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\mathbf{r} is not a constant.

I would suggest staying in Cartesian coordinates so that <br /> \frac{\partial \phi}{\partial x_i} = \frac1{4\pi\epsilon_0} \sum_j p_j \frac{\partial}{\partial x_i}\left(\frac{x_j}{r^3}\right) and using the results <br /> \frac{\partial r}{\partial x_i} = \frac{x_i}{r} and <br /> \frac{\partial x_j}{\partial x_i} = \begin{cases} 1, &amp; i = j, \\ 0, &amp; i \neq j.\end{cases}
 
Last edited:
pasmith said:
\mathbf{r} = r\hat{\mathbf{r}} is not a constant...
well if I plugged that in for r, wouldn't I just get

E = - (∂[p*rer/4πε0r3]/∂r)er = (p*er)/2πε0r3er ?
I haven't done vector calculus in a long time, idk if I am forgetting something obvious or what
 
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