Harmonic Motion-Just need to make sure

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A mass of 100 g is undergoing simple harmonic motion with a period of 0.993 seconds, and the goal is to determine the spring constant. The relevant formula used is T = 2π(m/k)^(1/2). The calculations involve rearranging the formula to find k, resulting in k = (2π*m)/T^2. The user is seeking confirmation of their solution before finalizing the answer. The discussion emphasizes the importance of verifying calculations in physics problems.
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Homework Statement


A mass of 100 g is hanging from a spring and is set into simple harmonic motion. If the period of the pendulum is 0.993 s, what is the spring constant?



Homework Equations



T=2pi(m/k)1/2

The Attempt at a Solution


I just want to make sure its right before I plug in the answer. Thanks.

T^2 = 2pi *(m/k)

k*T^2 = 2pi * m

k = (2pi*m)/T^2 = .637 N
 
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T^2 = 2pi *(m/k)

T^2 = 4(pi)^2*(m/k)
 
rl.bhat said:
T^2 = 2pi *(m/k)

T^2 = 4(pi)^2*(m/k)
kk, thanks. :)
 
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